Base | Representation |
---|---|
bin | 110000100111101001110… |
… | …110101000010100011001 |
3 | 102211101222220120011100220 |
4 | 300213221312220110121 |
5 | 414220044412014431 |
6 | 11034515222550253 |
7 | 463246615633011 |
oct | 60475166502431 |
9 | 12741886504326 |
10 | 3341113001241 |
11 | 1078a5a206354 |
12 | 45b643b98389 |
13 | 1b30b1194682 |
14 | b79d436ac41 |
15 | 5bd9b48cb96 |
hex | 309e9da8519 |
3341113001241 has 16 divisors (see below), whose sum is σ = 4462588658688. Its totient is φ = 2223526233600.
The previous prime is 3341113001207. The next prime is 3341113001267. The reversal of 3341113001241 is 1421003111433.
It is a happy number.
It is not a de Polignac number, because 3341113001241 - 214 = 3341112984857 is a prime.
It is a super-2 number, since 2×33411130012412 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3341113001201) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3750345 + ... + 4554921.
It is an arithmetic number, because the mean of its divisors is an integer number (278911791168).
Almost surely, 23341113001241 is an apocalyptic number.
It is an amenable number.
3341113001241 is a deficient number, since it is larger than the sum of its proper divisors (1121475657447).
3341113001241 is a wasteful number, since it uses less digits than its factorization.
3341113001241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 806992.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 3341113001241 its reverse (1421003111433), we get a palindrome (4762116112674).
The spelling of 3341113001241 in words is "three trillion, three hundred forty-one billion, one hundred thirteen million, one thousand, two hundred forty-one".
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