Search a number
-
+
334112525211433 is a prime number
BaseRepresentation
bin100101111110111111010001…
…0011000010101011100101001
31121210222211211100101001111211
41023331332202120111130221
5322243044422423231213
63142333101455153121
7130242555561534343
oct11375764230253451
91553884740331454
10334112525211433
1197505365205a51
12315812b48157a1
13114578a3055327
145c711bd83a293
15289607824653d
hex12fdfa2615729

334112525211433 has 2 divisors, whose sum is σ = 334112525211434. Its totient is φ = 334112525211432.

The previous prime is 334112525211391. The next prime is 334112525211461.

334112525211433 is nontrivially palindromic in base 10.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 227520177747984 + 106592347463449 = 15083772^2 + 10324357^2 .

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 334112525211433 - 237 = 333975086257961 is a prime.

It is a super-2 number, since 2×3341125252114332 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (334142525211433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167056262605716 + 167056262605717.

It is an arithmetic number, because the mean of its divisors is an integer number (167056262605717).

Almost surely, 2334112525211433 is an apocalyptic number.

It is an amenable number.

334112525211433 is a deficient number, since it is larger than the sum of its proper divisors (1).

334112525211433 is an equidigital number, since it uses as much as digits as its factorization.

334112525211433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 259200, while the sum is 40.

The spelling of 334112525211433 in words is "three hundred thirty-four trillion, one hundred twelve billion, five hundred twenty-five million, two hundred eleven thousand, four hundred thirty-three".