Base | Representation |
---|---|
bin | 1001101110010101100… |
… | …11101011000011011001 |
3 | 1011221102001100212100202 |
4 | 10313022303223003121 |
5 | 20433231421300423 |
6 | 413253524311545 |
7 | 33065452566062 |
oct | 4671263530331 |
9 | 1157361325322 |
10 | 334115025113 |
11 | 119774248631 |
12 | 549065425b5 |
13 | 256788b9abc |
14 | 12257cc3569 |
15 | 8a576ce728 |
hex | 4dcaceb0d9 |
334115025113 has 4 divisors (see below), whose sum is σ = 334375443408. Its totient is φ = 333854606820.
The previous prime is 334115025077. The next prime is 334115025121. The reversal of 334115025113 is 311520511433.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 334115025113 - 224 = 334098247897 is a prime.
It is a super-2 number, since 2×3341150251132 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (334115025143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130207223 + ... + 130209788.
It is an arithmetic number, because the mean of its divisors is an integer number (83593860852).
Almost surely, 2334115025113 is an apocalyptic number.
It is an amenable number.
334115025113 is a deficient number, since it is larger than the sum of its proper divisors (260418295).
334115025113 is a wasteful number, since it uses less digits than its factorization.
334115025113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 260418294.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 334115025113 its reverse (311520511433), we get a palindrome (645635536546).
The spelling of 334115025113 in words is "three hundred thirty-four billion, one hundred fifteen million, twenty-five thousand, one hundred thirteen".
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