334121404121433 has 12 divisors (see below), whose sum is σ = 482647120677540. Its totient is φ = 222734995951776.

The previous prime is 334121404121411. The next prime is 334121404121443.

334121404121433 is a `hidden beast` number, since 3 + 3 + 4 + 1 + 2 + 1 + 404 + 1 + 214 + 33 = 666.

334121404121433 is nontrivially palindromic in base 10.

It can be written as a sum of positive squares in 2 ways, for example, as 50398811020944 + 283722593100489 = 7099212^2 + 16844067^2 .

It is not a de Polignac number, because 334121404121433 - 2³⁰ = 334120330379609 is a prime.

It is a super-2 number, since 2×334121404121433² (a number of 30 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (334121404121443) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1050398466 + ... + 1050716507.

It is an arithmetic number, because the mean of its divisors is an integer number (40220593389795).

Almost surely, 2^{334121404121433} is an apocalyptic number.

It is an amenable number.

334121404121433 is a deficient number, since it is larger than the sum of its proper divisors (148525716556107).

334121404121433 is a wasteful number, since it uses less digits than its factorization.

334121404121433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2101132648 (or 2101132645 counting only the distinct ones).

The product of its (nonzero) digits is 82944, while the sum is 36.

It can be divided in two parts, 33412140 and 4121433, that added together give a palindrome (37533573).

The spelling of 334121404121433 in words is "three hundred thirty-four trillion, one hundred twenty-one billion, four hundred four million, one hundred twenty-one thousand, four hundred thirty-three".