Base | Representation |
---|---|
bin | 100101111111110110001110… |
… | …0110010100011000101010011 |
3 | 1121211102010110012200221001111 |
4 | 1023333230130302203011103 |
5 | 322302013123003122441 |
6 | 3142503220342314151 |
7 | 130254234301420144 |
oct | 11377543462430523 |
9 | 1554363405627044 |
10 | 334230543020371 |
11 | 97550417187638 |
12 | 315a0150728957 |
13 | 11465a6068c37a |
14 | 5c76bb7801acb |
15 | 28991841a6081 |
hex | 12ffb1cca3153 |
334230543020371 has 2 divisors, whose sum is σ = 334230543020372. Its totient is φ = 334230543020370.
The previous prime is 334230543020321. The next prime is 334230543020443. The reversal of 334230543020371 is 173020345032433.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-334230543020371 is a prime.
It is a super-2 number, since 2×3342305430203712 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (334230543020321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167115271510185 + 167115271510186.
It is an arithmetic number, because the mean of its divisors is an integer number (167115271510186).
Almost surely, 2334230543020371 is an apocalyptic number.
334230543020371 is a deficient number, since it is larger than the sum of its proper divisors (1).
334230543020371 is an equidigital number, since it uses as much as digits as its factorization.
334230543020371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 40.
The spelling of 334230543020371 in words is "three hundred thirty-four trillion, two hundred thirty billion, five hundred forty-three million, twenty thousand, three hundred seventy-one".
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