Base | Representation |
---|---|
bin | 100110000000100110011100… |
… | …1010101010100111000100010 |
3 | 1121211210000202100112011201121 |
4 | 1030001030321111110320202 |
5 | 322310212214341130102 |
6 | 3143022544331522454 |
7 | 130264561461613504 |
oct | 11401147125247042 |
9 | 1554700670464647 |
10 | 334334101114402 |
11 | 97590329009414 |
12 | 315b8231bb942a |
13 | 1147275539899c |
14 | 5c7bbdd223d74 |
15 | 289bbe5975b37 |
hex | 1301339554e22 |
334334101114402 has 4 divisors (see below), whose sum is σ = 501501151671606. Its totient is φ = 167167050557200.
The previous prime is 334334101114379. The next prime is 334334101114423. The reversal of 334334101114402 is 204411101433433.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 217111059926721 + 117223041187681 = 14734689^2 + 10826959^2 .
It is a super-2 number, since 2×3343341011144022 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83583525278599 + ... + 83583525278602.
Almost surely, 2334334101114402 is an apocalyptic number.
334334101114402 is a deficient number, since it is larger than the sum of its proper divisors (167167050557204).
334334101114402 is a wasteful number, since it uses less digits than its factorization.
334334101114402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 167167050557203.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 334334101114402 its reverse (204411101433433), we get a palindrome (538745202547835).
The spelling of 334334101114402 in words is "three hundred thirty-four trillion, three hundred thirty-four billion, one hundred one million, one hundred fourteen thousand, four hundred two".
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