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3344424113057 is a prime number
BaseRepresentation
bin110000101010101111001…
…101100001001110100001
3102211201112200000001212212
4300222233031201032201
5414243340033104212
611040223543331505
7463424642625146
oct60525715411641
912751480001785
103344424113057
11107a3a924a6a5
12460208a50b95
131b34bb167631
14b7c29dda3cd
155bee1ed7e22
hex30aaf3613a1

3344424113057 has 2 divisors, whose sum is σ = 3344424113058. Its totient is φ = 3344424113056.

The previous prime is 3344424112999. The next prime is 3344424113137. The reversal of 3344424113057 is 7503114244433.

3344424113057 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2687029094656 + 657395018401 = 1639216^2 + 810799^2 .

It is a cyclic number.

It is not a de Polignac number, because 3344424113057 - 26 = 3344424112993 is a prime.

It is a super-3 number, since 3×33444241130573 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (3344424110057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1672212056528 + 1672212056529.

It is an arithmetic number, because the mean of its divisors is an integer number (1672212056529).

Almost surely, 23344424113057 is an apocalyptic number.

It is an amenable number.

3344424113057 is a deficient number, since it is larger than the sum of its proper divisors (1).

3344424113057 is an equidigital number, since it uses as much as digits as its factorization.

3344424113057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 483840, while the sum is 41.

The spelling of 3344424113057 in words is "three trillion, three hundred forty-four billion, four hundred twenty-four million, one hundred thirteen thousand, fifty-seven".