Base | Representation |
---|---|
bin | 110000110000000001100… |
… | …010110101110010111110 |
3 | 102212021012020221101120022 |
4 | 300300001202311302332 |
5 | 414342001200320332 |
6 | 11043003114052142 |
7 | 464015416365452 |
oct | 60600142656276 |
9 | 12767166841508 |
10 | 3350100401342 |
11 | 1081851381042 |
12 | 461331a1a052 |
13 | 1b3bb41528b6 |
14 | b8207c22662 |
15 | 5c2254cb212 |
hex | 30c018b5cbe |
3350100401342 has 16 divisors (see below), whose sum is σ = 5187409928064. Its totient is φ = 1620967044000.
The previous prime is 3350100401341. The next prime is 3350100401363. The reversal of 3350100401342 is 2431040010533.
It is a super-3 number, since 3×33501004013423 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3350100401341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1277492 + ... + 2886552.
It is an arithmetic number, because the mean of its divisors is an integer number (324213120504).
Almost surely, 23350100401342 is an apocalyptic number.
3350100401342 is a deficient number, since it is larger than the sum of its proper divisors (1837309526722).
3350100401342 is a wasteful number, since it uses less digits than its factorization.
3350100401342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1642675.
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 3350100401342 its reverse (2431040010533), we get a palindrome (5781140411875).
The spelling of 3350100401342 in words is "three trillion, three hundred fifty billion, one hundred million, four hundred one thousand, three hundred forty-two".
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