3352013441 has 4 divisors (see below), whose sum is σ = 3830872512. Its totient is φ = 2873154372.

The previous prime is 3352013393. The next prime is 3352013513. The reversal of 3352013441 is 1443102533.

3352013441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3352013441 is a prime.

It is a super-2 number, since 2×3352013441² = 22471988217289320962, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 3352013441.

It is not an unprimeable number, because it can be changed into a prime (3352013341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 239429525 + ... + 239429538.

It is an arithmetic number, because the mean of its divisors is an integer number (957718128).

Almost surely, 2^3352013441 is an apocalyptic number.

It is an amenable number.

3352013441 is a deficient number, since it is larger than the sum of its proper divisors (478859071).

3352013441 is an equidigital number, since it uses as much as digits as its factorization.

3352013441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 478859070.

The product of its (nonzero) digits is 4320, while the sum is 26.

The square root of 3352013441 is about 57896.5753823143. The cubic root of 3352013441 is about 1496.5868232255.

Adding to 3352013441 its reverse (1443102533), we get a palindrome (4795115974).

The spelling of 3352013441 in words is "three billion, three hundred fifty-two million, thirteen thousand, four hundred forty-one".