33540433 has 4 divisors (see below), whose sum is σ = 33599140. Its totient is φ = 33481728.

The previous prime is 33540427. The next prime is 33540457. The reversal of 33540433 is 33404533.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 32913169 + 627264 = 5737^2 + 792^2 .

It is a cyclic number.

It is not a de Polignac number, because 33540433 - 2¹⁷ = 33409361 is a prime.

It is a super-2 number, since 2×33540433² = 2249921291654978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 33540398 and 33540407.

It is not an unprimeable number, because it can be changed into a prime (33540413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28488 + ... + 29641.

It is an arithmetic number, because the mean of its divisors is an integer number (8399785).

Almost surely, 2^33540433 is an apocalyptic number.

It is an amenable number.

33540433 is a deficient number, since it is larger than the sum of its proper divisors (58707).

33540433 is an equidigital number, since it uses as much as digits as its factorization.

33540433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58706.

The product of its (nonzero) digits is 6480, while the sum is 25.

The square root of 33540433 is about 5791.4102772986. The cubic root of 33540433 is about 322.4949277090.

Adding to 33540433 its reverse (33404533), we get a palindrome (66944966).

The spelling of 33540433 in words is "thirty-three million, five hundred forty thousand, four hundred thirty-three".