Base | Representation |
---|---|
bin | 1001111001010011011… |
… | …01011101100111000011 |
3 | 1012111121100010100002012 |
4 | 10330221231131213003 |
5 | 21032311030400003 |
6 | 420110031043135 |
7 | 33364400005214 |
oct | 4745155354703 |
9 | 1174540110065 |
10 | 340002200003 |
11 | 121215418224 |
12 | 55a8a0704ab |
13 | 260a64a163b |
14 | 12655b2340b |
15 | 8c9e47c8d8 |
hex | 4f29b5d9c3 |
340002200003 has 2 divisors, whose sum is σ = 340002200004. Its totient is φ = 340002200002.
The previous prime is 340002199991. The next prime is 340002200011. The reversal of 340002200003 is 300002200043.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 340002200003 - 210 = 340002198979 is a prime.
It is not a weakly prime, because it can be changed into another prime (340002200023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170001100001 + 170001100002.
It is an arithmetic number, because the mean of its divisors is an integer number (170001100002).
Almost surely, 2340002200003 is an apocalyptic number.
340002200003 is a deficient number, since it is larger than the sum of its proper divisors (1).
340002200003 is an equidigital number, since it uses as much as digits as its factorization.
340002200003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 14.
Adding to 340002200003 its reverse (300002200043), we get a palindrome (640004400046).
The spelling of 340002200003 in words is "three hundred forty billion, two million, two hundred thousand, three".
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