Base | Representation |
---|---|
bin | 1111011101100010010111… |
… | …10111101110000111001011 |
3 | 11110101101112202201120002021 |
4 | 13232301023313232013023 |
5 | 13424024434401410011 |
6 | 200151254124545311 |
7 | 10106302331441341 |
oct | 756611367560713 |
9 | 143341482646067 |
10 | 34000234013131 |
11 | a919466797201 |
12 | 39915816b2237 |
13 | 15c8292870799 |
14 | 857897803991 |
15 | 3de6565ab471 |
hex | 1eec4bdee1cb |
34000234013131 has 2 divisors, whose sum is σ = 34000234013132. Its totient is φ = 34000234013130.
The previous prime is 34000234013047. The next prime is 34000234013147. The reversal of 34000234013131 is 13131043200043.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34000234013131 is a prime.
It is a super-2 number, since 2×340002340131312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 34000234013096 and 34000234013105.
It is not a weakly prime, because it can be changed into another prime (34000234013171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17000117006565 + 17000117006566.
It is an arithmetic number, because the mean of its divisors is an integer number (17000117006566).
Almost surely, 234000234013131 is an apocalyptic number.
34000234013131 is a deficient number, since it is larger than the sum of its proper divisors (1).
34000234013131 is an equidigital number, since it uses as much as digits as its factorization.
34000234013131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 34000234013131 its reverse (13131043200043), we get a palindrome (47131277213174).
The spelling of 34000234013131 in words is "thirty-four trillion, two hundred thirty-four million, thirteen thousand, one hundred thirty-one".
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