Base | Representation |
---|---|
bin | 1001111001010011100… |
… | …01110010000101010001 |
3 | 1012111121102020212111001 |
4 | 10330221301302011101 |
5 | 21032311323114213 |
6 | 420110111222001 |
7 | 33364412432602 |
oct | 4745161620521 |
9 | 1174542225431 |
10 | 340003332433 |
11 | 121216021016 |
12 | 55a8a517901 |
13 | 260a67a9c0b |
14 | 12655d39da9 |
15 | 8c9e6031dd |
hex | 4f29c72151 |
340003332433 has 2 divisors, whose sum is σ = 340003332434. Its totient is φ = 340003332432.
The previous prime is 340003332419. The next prime is 340003332457. The reversal of 340003332433 is 334233300043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 339902992144 + 100340289 = 583012^2 + 10017^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-340003332433 is a prime.
It is a super-4 number, since 4×3400033324334 (a number of 47 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (340003332463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170001666216 + 170001666217.
It is an arithmetic number, because the mean of its divisors is an integer number (170001666217).
Almost surely, 2340003332433 is an apocalyptic number.
It is an amenable number.
340003332433 is a deficient number, since it is larger than the sum of its proper divisors (1).
340003332433 is an equidigital number, since it uses as much as digits as its factorization.
340003332433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 28.
Adding to 340003332433 its reverse (334233300043), we get a palindrome (674236632476).
The spelling of 340003332433 in words is "three hundred forty billion, three million, three hundred thirty-two thousand, four hundred thirty-three".
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