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340014023021401 is a prime number
BaseRepresentation
bin100110101001111011010111…
…1000011111001001101011001
31122120220000121212122220011121
41031103312233003321031121
5324031242204343141101
63203052141422325241
7131422126313334121
oct11523665703711531
91576800555586147
10340014023021401
1199380156937083
1232174bb4429821
1311795252cabb81
145dd6aa349bc81
15294982970a0a1
hex1353daf0f9359

340014023021401 has 2 divisors, whose sum is σ = 340014023021402. Its totient is φ = 340014023021400.

The previous prime is 340014023021347. The next prime is 340014023021419. The reversal of 340014023021401 is 104120320410043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 177332900889600 + 162681122131801 = 13316640^2 + 12754651^2 .

It is a cyclic number.

It is not a de Polignac number, because 340014023021401 - 211 = 340014023019353 is a prime.

It is not a weakly prime, because it can be changed into another prime (340014023021201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170007011510700 + 170007011510701.

It is an arithmetic number, because the mean of its divisors is an integer number (170007011510701).

Almost surely, 2340014023021401 is an apocalyptic number.

It is an amenable number.

340014023021401 is a deficient number, since it is larger than the sum of its proper divisors (1).

340014023021401 is an equidigital number, since it uses as much as digits as its factorization.

340014023021401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 340014023021401 its reverse (104120320410043), we get a palindrome (444134343431444).

The spelling of 340014023021401 in words is "three hundred forty trillion, fourteen billion, twenty-three million, twenty-one thousand, four hundred one".