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34003241412137 is a prime number
BaseRepresentation
bin1111011101100111111110…
…01000000010011000101001
311110101200022100200020221122
413232303333020002120221
513424102114300142022
6200152512355545025
710106440010061434
oct756637710023051
9143350270606848
1034003241412137
11a91a76a350628
1239920808bb175
1315c8651945a1a
14857aa0db481b
153de780612742
hex1eecff202629

34003241412137 has 2 divisors, whose sum is σ = 34003241412138. Its totient is φ = 34003241412136.

The previous prime is 34003241412109. The next prime is 34003241412157. The reversal of 34003241412137 is 73121414230043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30488276381161 + 3514965030976 = 5521619^2 + 1874824^2 .

It is an emirp because it is prime and its reverse (73121414230043) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34003241412137 - 216 = 34003241346601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34003241412097 and 34003241412106.

It is not a weakly prime, because it can be changed into another prime (34003241412157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17001620706068 + 17001620706069.

It is an arithmetic number, because the mean of its divisors is an integer number (17001620706069).

Almost surely, 234003241412137 is an apocalyptic number.

It is an amenable number.

34003241412137 is a deficient number, since it is larger than the sum of its proper divisors (1).

34003241412137 is an equidigital number, since it uses as much as digits as its factorization.

34003241412137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 35.

The spelling of 34003241412137 in words is "thirty-four trillion, three billion, two hundred forty-one million, four hundred twelve thousand, one hundred thirty-seven".