Base | Representation |
---|---|
bin | 1001111001010111000… |
… | …01000110010110101011 |
3 | 1012111200110011102022111 |
4 | 10330223201012112223 |
5 | 21032341310412301 |
6 | 420113032503151 |
7 | 33365215450501 |
oct | 4745341062653 |
9 | 1174613142274 |
10 | 340032513451 |
11 | 121230542164 |
12 | 55a9824aab7 |
13 | 260ac8561a7 |
14 | 12659b74671 |
15 | 8ca1e69551 |
hex | 4f2b8465ab |
340032513451 has 4 divisors (see below), whose sum is σ = 341911146304. Its totient is φ = 338153880600.
The previous prime is 340032513409. The next prime is 340032513473. The reversal of 340032513451 is 154315230043.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 340032513451 - 27 = 340032513323 is a prime.
It is a super-2 number, since 2×3400325134512 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (340032513481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 939316155 + ... + 939316516.
It is an arithmetic number, because the mean of its divisors is an integer number (85477786576).
Almost surely, 2340032513451 is an apocalyptic number.
340032513451 is a deficient number, since it is larger than the sum of its proper divisors (1878632853).
340032513451 is a wasteful number, since it uses less digits than its factorization.
340032513451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1878632852.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 340032513451 its reverse (154315230043), we get a palindrome (494347743494).
The spelling of 340032513451 in words is "three hundred forty billion, thirty-two million, five hundred thirteen thousand, four hundred fifty-one".
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