Base | Representation |
---|---|
bin | 1001111001010111000… |
… | …01000110100000000011 |
3 | 1012111200110011110010201 |
4 | 10330223201012200003 |
5 | 21032341310422201 |
6 | 420113032510031 |
7 | 33365215452316 |
oct | 4745341064003 |
9 | 1174613143121 |
10 | 340032514051 |
11 | 12123054265a |
12 | 55a9824b317 |
13 | 260ac856549 |
14 | 12659b7497d |
15 | 8ca1e69801 |
hex | 4f2b846803 |
340032514051 has 2 divisors, whose sum is σ = 340032514052. Its totient is φ = 340032514050.
The previous prime is 340032514037. The next prime is 340032514061. The reversal of 340032514051 is 150415230043.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 340032514051 - 229 = 339495643139 is a prime.
It is a super-2 number, since 2×3400325140512 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (340032514061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170016257025 + 170016257026.
It is an arithmetic number, because the mean of its divisors is an integer number (170016257026).
Almost surely, 2340032514051 is an apocalyptic number.
340032514051 is a deficient number, since it is larger than the sum of its proper divisors (1).
340032514051 is an equidigital number, since it uses as much as digits as its factorization.
340032514051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 340032514051 its reverse (150415230043), we get a palindrome (490447744094).
The spelling of 340032514051 in words is "three hundred forty billion, thirty-two million, five hundred fourteen thousand, fifty-one".
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