340032540401 has 4 divisors (see below), whose sum is σ = 345606844404. Its totient is φ = 334458236400.

The previous prime is 340032540389. The next prime is 340032540427. The reversal of 340032540401 is 104045230043.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 21088848400 + 318943692001 = 145220^2 + 564751^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-340032540401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (340032545401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2787151910 + ... + 2787152031.

It is an arithmetic number, because the mean of its divisors is an integer number (86401711101).

Almost surely, 2^340032540401 is an apocalyptic number.

It is an amenable number.

340032540401 is a deficient number, since it is larger than the sum of its proper divisors (5574304003).

340032540401 is an equidigital number, since it uses as much as digits as its factorization.

340032540401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5574304002.

The product of its (nonzero) digits is 5760, while the sum is 26.

Adding to 340032540401 its reverse (104045230043), we get a palindrome (444077770444).

The spelling of 340032540401 in words is "three hundred forty billion, thirty-two million, five hundred forty thousand, four hundred one".