Base | Representation |
---|---|
bin | 1111011101101010000001… |
… | …10000000110010011110011 |
3 | 11110101210011002102220122112 |
4 | 13232311000300012103303 |
5 | 13424111343130324021 |
6 | 200153213530355535 |
7 | 10106506206436016 |
oct | 756650060062363 |
9 | 143353132386575 |
10 | 34004342433011 |
11 | a9201848a2935 |
12 | 399232958bbab |
13 | 15c8798a93272 |
14 | 857b672db37d |
15 | 3de7e70ead5b |
hex | 1eed40c064f3 |
34004342433011 has 2 divisors, whose sum is σ = 34004342433012. Its totient is φ = 34004342433010.
The previous prime is 34004342433007. The next prime is 34004342433073. The reversal of 34004342433011 is 11033424340043.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 34004342433011 - 22 = 34004342433007 is a prime.
It is a super-2 number, since 2×340043424330112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (34004342433091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17002171216505 + 17002171216506.
It is an arithmetic number, because the mean of its divisors is an integer number (17002171216506).
Almost surely, 234004342433011 is an apocalyptic number.
34004342433011 is a deficient number, since it is larger than the sum of its proper divisors (1).
34004342433011 is an equidigital number, since it uses as much as digits as its factorization.
34004342433011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 34004342433011 its reverse (11033424340043), we get a palindrome (45037766773054).
The spelling of 34004342433011 in words is "thirty-four trillion, four billion, three hundred forty-two million, four hundred thirty-three thousand, eleven".
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