Base | Representation |
---|---|
bin | 110001011111010111110… |
… | …110110110001000000001 |
3 | 110001010102101202120212011 |
4 | 301133113312312020001 |
5 | 421210111244010144 |
6 | 11122212012132521 |
7 | 500465323132333 |
oct | 61372766661001 |
9 | 13033371676764 |
10 | 3400940610049 |
11 | 10a1370348354 |
12 | 46b160167141 |
13 | 1b8926cb3028 |
14 | ba86bd87453 |
15 | 5d6ed9dba34 |
hex | 317d7db6201 |
3400940610049 has 2 divisors, whose sum is σ = 3400940610050. Its totient is φ = 3400940610048.
The previous prime is 3400940609959. The next prime is 3400940610079. The reversal of 3400940610049 is 9400160490043.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3399388250049 + 1552360000 = 1843743^2 + 39400^2 .
It is a cyclic number.
It is not a de Polignac number, because 3400940610049 - 27 = 3400940609921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3400940609993 and 3400940610020.
It is not a weakly prime, because it can be changed into another prime (3400940610079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700470305024 + 1700470305025.
It is an arithmetic number, because the mean of its divisors is an integer number (1700470305025).
Almost surely, 23400940610049 is an apocalyptic number.
It is an amenable number.
3400940610049 is a deficient number, since it is larger than the sum of its proper divisors (1).
3400940610049 is an equidigital number, since it uses as much as digits as its factorization.
3400940610049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 40.
The spelling of 3400940610049 in words is "three trillion, four hundred billion, nine hundred forty million, six hundred ten thousand, forty-nine".
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