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340101505441 is a prime number
BaseRepresentation
bin1001111001011111010…
…00010010000110100001
31012111212020222120112101
410330233220102012201
521033011441133231
6420123535330401
733400014045355
oct4745750220641
91174766876471
10340101505441
11121266484935
1255ab7380a01
13260c0c30c59
1412664db3465
158ca8046661
hex4f2fa121a1

340101505441 has 2 divisors, whose sum is σ = 340101505442. Its totient is φ = 340101505440.

The previous prime is 340101505361. The next prime is 340101505463. The reversal of 340101505441 is 144505101043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 319739357025 + 20362148416 = 565455^2 + 142696^2 .

It is an emirp because it is prime and its reverse (144505101043) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 340101505441 - 211 = 340101503393 is a prime.

It is not a weakly prime, because it can be changed into another prime (340101505841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170050752720 + 170050752721.

It is an arithmetic number, because the mean of its divisors is an integer number (170050752721).

Almost surely, 2340101505441 is an apocalyptic number.

It is an amenable number.

340101505441 is a deficient number, since it is larger than the sum of its proper divisors (1).

340101505441 is an equidigital number, since it uses as much as digits as its factorization.

340101505441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 340101505441 its reverse (144505101043), we get a palindrome (484606606484).

The spelling of 340101505441 in words is "three hundred forty billion, one hundred one million, five hundred five thousand, four hundred forty-one".