Base | Representation |
---|---|
bin | 110001011111011100110… |
… | …110101000011101011001 |
3 | 110001010122020111121010211 |
4 | 301133130312220131121 |
5 | 421210244224041103 |
6 | 11122224205011121 |
7 | 500500361520064 |
oct | 61373466503531 |
9 | 13033566447124 |
10 | 3401024440153 |
11 | 10a14036a512a |
12 | 46b184253aa1 |
13 | 1b893b484842 |
14 | ba8791698db |
15 | 5d70604a36d |
hex | 317dcda8759 |
3401024440153 has 2 divisors, whose sum is σ = 3401024440154. Its totient is φ = 3401024440152.
The previous prime is 3401024440147. The next prime is 3401024440171. The reversal of 3401024440153 is 3510444201043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2765475872784 + 635548567369 = 1662972^2 + 797213^2 .
It is a cyclic number.
It is not a de Polignac number, because 3401024440153 - 221 = 3401022343001 is a prime.
It is not a weakly prime, because it can be changed into another prime (3401024470153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700512220076 + 1700512220077.
It is an arithmetic number, because the mean of its divisors is an integer number (1700512220077).
Almost surely, 23401024440153 is an apocalyptic number.
It is an amenable number.
3401024440153 is a deficient number, since it is larger than the sum of its proper divisors (1).
3401024440153 is an equidigital number, since it uses as much as digits as its factorization.
3401024440153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 3401024440153 its reverse (3510444201043), we get a palindrome (6911468641196).
The spelling of 3401024440153 in words is "three trillion, four hundred one billion, twenty-four million, four hundred forty thousand, one hundred fifty-three".
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