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34011134312497 is a prime number
BaseRepresentation
bin1111011101110110101011…
…00101000100000000110001
311110102102200102120010202121
413232323111211010000301
513424214300340444442
6200200255512114241
710110136420446646
oct756732545040061
9143372612503677
1034011134312497
11a92304a718481
123993704095981
1315c930bc2a974
1485820d35ddcd
153dea93504967
hex1eeed5944031

34011134312497 has 2 divisors, whose sum is σ = 34011134312498. Its totient is φ = 34011134312496.

The previous prime is 34011134312429. The next prime is 34011134312513. The reversal of 34011134312497 is 79421343111043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31661339639281 + 2349794673216 = 5626841^2 + 1532904^2 .

It is an emirp because it is prime and its reverse (79421343111043) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34011134312497 - 235 = 33976774574129 is a prime.

It is not a weakly prime, because it can be changed into another prime (34011134112497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17005567156248 + 17005567156249.

It is an arithmetic number, because the mean of its divisors is an integer number (17005567156249).

Almost surely, 234011134312497 is an apocalyptic number.

It is an amenable number.

34011134312497 is a deficient number, since it is larger than the sum of its proper divisors (1).

34011134312497 is an equidigital number, since it uses as much as digits as its factorization.

34011134312497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 217728, while the sum is 43.

The spelling of 34011134312497 in words is "thirty-four trillion, eleven billion, one hundred thirty-four million, three hundred twelve thousand, four hundred ninety-seven".