Base | Representation |
---|---|
bin | 1111011101111000010011… |
… | …11010110100011101101011 |
3 | 11110102111221121220012011221 |
4 | 13232330021322310131223 |
5 | 13424223100140244321 |
6 | 200200523001202511 |
7 | 10110200242362553 |
oct | 756741172643553 |
9 | 143374847805157 |
10 | 34012012431211 |
11 | a923460365021 |
12 | 399390a190437 |
13 | 15c941bb32839 |
14 | 858293c22163 |
15 | 3deae565ce41 |
hex | 1eef09eb476b |
34012012431211 has 4 divisors (see below), whose sum is σ = 34271646114024. Its totient is φ = 33752378748400.
The previous prime is 34012012431203. The next prime is 34012012431253. The reversal of 34012012431211 is 11213421021043.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 34012012431211 - 23 = 34012012431203 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34012012431811) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129816841210 + ... + 129816841471.
It is an arithmetic number, because the mean of its divisors is an integer number (8567911528506).
Almost surely, 234012012431211 is an apocalyptic number.
34012012431211 is a deficient number, since it is larger than the sum of its proper divisors (259633682813).
34012012431211 is a wasteful number, since it uses less digits than its factorization.
34012012431211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 259633682812.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 34012012431211 its reverse (11213421021043), we get a palindrome (45225433452254).
The spelling of 34012012431211 in words is "thirty-four trillion, twelve billion, twelve million, four hundred thirty-one thousand, two hundred eleven".
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