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3401212243553 is a prime number
BaseRepresentation
bin110001011111101000000…
…011000010111001100001
3110001011010022212222222022
4301133220003002321201
5421211140313243203
611122254554151225
7500505132025625
oct61375003027141
913034108788868
103401212243553
1110a149a707653
1246b217122515
131b896b35b507
14ba896095185
155d717795a38
hex317e80c2e61

3401212243553 has 2 divisors, whose sum is σ = 3401212243554. Its totient is φ = 3401212243552.

The previous prime is 3401212243537. The next prime is 3401212243591. The reversal of 3401212243553 is 3553422121043.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2621977039504 + 779235204049 = 1619252^2 + 882743^2 .

It is a cyclic number.

It is not a de Polignac number, because 3401212243553 - 24 = 3401212243537 is a prime.

It is not a weakly prime, because it can be changed into another prime (3401212243523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700606121776 + 1700606121777.

It is an arithmetic number, because the mean of its divisors is an integer number (1700606121777).

Almost surely, 23401212243553 is an apocalyptic number.

It is an amenable number.

3401212243553 is a deficient number, since it is larger than the sum of its proper divisors (1).

3401212243553 is an equidigital number, since it uses as much as digits as its factorization.

3401212243553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 3401212243553 its reverse (3553422121043), we get a palindrome (6954634364596).

The spelling of 3401212243553 in words is "three trillion, four hundred one billion, two hundred twelve million, two hundred forty-three thousand, five hundred fifty-three".