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34013340402001 is a prime number
BaseRepresentation
bin1111011101111010110010…
…00100101000000101010001
311110102122101011201002122021
413232331121010220011101
513424233310120331001
6200201302440211441
710110245166060532
oct756753104500521
9143378334632567
1034013340402001
11a923a81a27144
12399401aa69b81
1315c95a0cb1c7c
1485837c344689
153deb72025ba1
hex1eef59128151

34013340402001 has 2 divisors, whose sum is σ = 34013340402002. Its totient is φ = 34013340402000.

The previous prime is 34013340401983. The next prime is 34013340402017. The reversal of 34013340402001 is 10020404331043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20828489502976 + 13184850899025 = 4563824^2 + 3631095^2 .

It is an emirp because it is prime and its reverse (10020404331043) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34013340402001 - 241 = 31814317146449 is a prime.

It is not a weakly prime, because it can be changed into another prime (34013340402071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17006670201000 + 17006670201001.

It is an arithmetic number, because the mean of its divisors is an integer number (17006670201001).

Almost surely, 234013340402001 is an apocalyptic number.

It is an amenable number.

34013340402001 is a deficient number, since it is larger than the sum of its proper divisors (1).

34013340402001 is an equidigital number, since it uses as much as digits as its factorization.

34013340402001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 34013340402001 its reverse (10020404331043), we get a palindrome (44033744733044).

The spelling of 34013340402001 in words is "thirty-four trillion, thirteen billion, three hundred forty million, four hundred two thousand, one".