Base | Representation |
---|---|
bin | 11111101011011001… |
… | …001111010001101011 |
3 | 10020210111101220111010 |
4 | 133223121033101223 |
5 | 1024130043024003 |
6 | 23343102435003 |
7 | 2312620336656 |
oct | 375331172153 |
9 | 106714356433 |
10 | 34014033003 |
11 | 13475042485 |
12 | 6713292a63 |
13 | 3290b8ac62 |
14 | 19095b289d |
15 | d41222003 |
hex | 7eb64f46b |
34014033003 has 4 divisors (see below), whose sum is σ = 45352044008. Its totient is φ = 22676022000.
The previous prime is 34014032953. The next prime is 34014033037. The reversal of 34014033003 is 30033041043.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30033041043 = 3 ⋅10011013681.
It is not a de Polignac number, because 34014033003 - 29 = 34014032491 is a prime.
It is a super-2 number, since 2×340140330032 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34014033203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5669005498 + ... + 5669005503.
It is an arithmetic number, because the mean of its divisors is an integer number (11338011002).
Almost surely, 234014033003 is an apocalyptic number.
34014033003 is a deficient number, since it is larger than the sum of its proper divisors (11338011005).
34014033003 is a wasteful number, since it uses less digits than its factorization.
34014033003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11338011004.
The product of its (nonzero) digits is 1296, while the sum is 21.
Adding to 34014033003 its reverse (30033041043), we get a palindrome (64047074046).
The spelling of 34014033003 in words is "thirty-four billion, fourteen million, thirty-three thousand, three".
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