Base | Representation |
---|---|
bin | 11111101011011010… |
… | …110010111000101001 |
3 | 10020210112011122011011 |
4 | 133223122302320221 |
5 | 1024130144103001 |
6 | 23343115303521 |
7 | 2312623656322 |
oct | 375332627051 |
9 | 106715148134 |
10 | 34014441001 |
11 | 134752a0a72 |
12 | 671344aba1 |
13 | 3290ca1888 |
14 | 190967b449 |
15 | d412a2d51 |
hex | 7eb6b2e29 |
34014441001 has 2 divisors, whose sum is σ = 34014441002. Its totient is φ = 34014441000.
The previous prime is 34014440987. The next prime is 34014441101. The reversal of 34014441001 is 10014441043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32283464976 + 1730976025 = 179676^2 + 41605^2 .
It is an emirp because it is prime and its reverse (10014441043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34014441001 - 223 = 34006052393 is a prime.
It is a super-2 number, since 2×340144410012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (34014441101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17007220500 + 17007220501.
It is an arithmetic number, because the mean of its divisors is an integer number (17007220501).
Almost surely, 234014441001 is an apocalyptic number.
It is an amenable number.
34014441001 is a deficient number, since it is larger than the sum of its proper divisors (1).
34014441001 is an equidigital number, since it uses as much as digits as its factorization.
34014441001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 34014441001 its reverse (10014441043), we get a palindrome (44028882044).
The spelling of 34014441001 in words is "thirty-four billion, fourteen million, four hundred forty-one thousand, one".
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