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34023153433 is a prime number
BaseRepresentation
bin11111101011111100…
…000001111100011001
310020211010120021100211
4133223330001330121
51024134411402213
623344030131121
72313061014103
oct375374017431
9106733507324
1034023153433
111347a201825
126716350aa1
133292a32369
14190a8a8573
15d41e2453d
hex7ebf01f19

34023153433 has 2 divisors, whose sum is σ = 34023153434. Its totient is φ = 34023153432.

The previous prime is 34023153421. The next prime is 34023153497. The reversal of 34023153433 is 33435132043.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20389555264 + 13633598169 = 142792^2 + 116763^2 .

It is an emirp because it is prime and its reverse (33435132043) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34023153433 - 221 = 34021056281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34023153395 and 34023153404.

It is not a weakly prime, because it can be changed into another prime (34023157433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17011576716 + 17011576717.

It is an arithmetic number, because the mean of its divisors is an integer number (17011576717).

Almost surely, 234023153433 is an apocalyptic number.

It is an amenable number.

34023153433 is a deficient number, since it is larger than the sum of its proper divisors (1).

34023153433 is an equidigital number, since it uses as much as digits as its factorization.

34023153433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 31.

Adding to 34023153433 its reverse (33435132043), we get a palindrome (67458285476).

The spelling of 34023153433 in words is "thirty-four billion, twenty-three million, one hundred fifty-three thousand, four hundred thirty-three".