Base | Representation |
---|---|
bin | 1111011110011100011111… |
… | …00000011110011011110001 |
3 | 11110111101002010010210211212 |
4 | 13233032033200132123301 |
5 | 13430032333441310421 |
6 | 200213454051045505 |
7 | 10111455435162134 |
oct | 757161740363361 |
9 | 143441063123755 |
10 | 34031433541361 |
11 | a930717044583 |
12 | 399762a2a0895 |
13 | 15cb1c55c33a9 |
14 | 8591b729821b |
15 | 3e038067ae5b |
hex | 1ef38f81e6f1 |
34031433541361 has 2 divisors, whose sum is σ = 34031433541362. Its totient is φ = 34031433541360.
The previous prime is 34031433541319. The next prime is 34031433541373. The reversal of 34031433541361 is 16314533413043.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23300469627136 + 10730963914225 = 4827056^2 + 3275815^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34031433541361 is a prime.
It is not a weakly prime, because it can be changed into another prime (34031433541381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17015716770680 + 17015716770681.
It is an arithmetic number, because the mean of its divisors is an integer number (17015716770681).
Almost surely, 234031433541361 is an apocalyptic number.
It is an amenable number.
34031433541361 is a deficient number, since it is larger than the sum of its proper divisors (1).
34031433541361 is an equidigital number, since it uses as much as digits as its factorization.
34031433541361 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 466560, while the sum is 41.
The spelling of 34031433541361 in words is "thirty-four trillion, thirty-one billion, four hundred thirty-three million, five hundred forty-one thousand, three hundred sixty-one".
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