3404112314113 has 4 divisors (see below), whose sum is σ = 3890414073280. Its totient is φ = 2917810554948.

The previous prime is 3404112314107. The next prime is 3404112314117. The reversal of 3404112314113 is 3114132114043.

3404112314113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3404112314113 - 2⁵ = 3404112314081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3404112314117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 243150879573 + ... + 243150879586.

It is an arithmetic number, because the mean of its divisors is an integer number (972603518320).

Almost surely, 2^{3404112314113} is an apocalyptic number.

It is an amenable number.

3404112314113 is a deficient number, since it is larger than the sum of its proper divisors (486301759167).

3404112314113 is an equidigital number, since it uses as much as digits as its factorization.

3404112314113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 486301759166.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 3404112314113 its reverse (3114132114043), we get a palindrome (6518244428156).

The spelling of 3404112314113 in words is "three trillion, four hundred four billion, one hundred twelve million, three hundred fourteen thousand, one hundred thirteen".