Base | Representation |
---|---|
bin | 110001100010010100111… |
… | …101010111101010100001 |
3 | 110001102121111120120110101 |
4 | 301202110331113222201 |
5 | 421233110440322423 |
6 | 11123454504102401 |
7 | 500640045621013 |
oct | 61422475275241 |
9 | 13042544516411 |
10 | 3404113214113 |
11 | 10a2749189787 |
12 | 46b8a6764a01 |
13 | 1b901137bc41 |
14 | baa8d4801b3 |
15 | 5d8372c77ad |
hex | 31894f57aa1 |
3404113214113 has 8 divisors (see below), whose sum is σ = 3411521127936. Its totient is φ = 3396708650400.
The previous prime is 3404113214101. The next prime is 3404113214147. The reversal of 3404113214113 is 3114123114043.
3404113214113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3404113214113 - 29 = 3404113213601 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3404113214813) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1202320 + ... + 2872942.
It is an arithmetic number, because the mean of its divisors is an integer number (426440140992).
Almost surely, 23404113214113 is an apocalyptic number.
It is an amenable number.
3404113214113 is a deficient number, since it is larger than the sum of its proper divisors (7407913823).
3404113214113 is a wasteful number, since it uses less digits than its factorization.
3404113214113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1675055.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 3404113214113 its reverse (3114123114043), we get a palindrome (6518236328156).
The spelling of 3404113214113 in words is "three trillion, four hundred four billion, one hundred thirteen million, two hundred fourteen thousand, one hundred thirteen".
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