341002443340401 has 4 divisors (see below), whose sum is σ = 454669924453872. Its totient is φ = 227334962226932.

The previous prime is 341002443340381. The next prime is 341002443340409. The reversal of 341002443340401 is 104043344200143.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 341002443340401 - 2²¹ = 341002441243249 is a prime.

It is not an unprimeable number, because it can be changed into a prime (341002443340409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56833740556731 + ... + 56833740556736.

It is an arithmetic number, because the mean of its divisors is an integer number (113667481113468).

Almost surely, 2^{341002443340401} is an apocalyptic number.

It is an amenable number.

341002443340401 is a deficient number, since it is larger than the sum of its proper divisors (113667481113471).

341002443340401 is a wasteful number, since it uses less digits than its factorization.

341002443340401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113667481113470.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 341002443340401 its reverse (104043344200143), we get a palindrome (445045787540544).

The spelling of 341002443340401 in words is "three hundred forty-one trillion, two billion, four hundred forty-three million, three hundred forty thousand, four hundred one".