Base | Representation |
---|---|
bin | 1001111011001110001… |
… | …11111001111110110011 |
3 | 1012121021010220010202202 |
4 | 10331213013321332303 |
5 | 21041413312322011 |
6 | 420400154533415 |
7 | 33432050531141 |
oct | 4754707717663 |
9 | 1177233803682 |
10 | 341032542131 |
11 | 1216a3a85546 |
12 | 5611713726b |
13 | 2620baa3438 |
14 | 127128cc591 |
15 | 8d0eb5423b |
hex | 4f671f9fb3 |
341032542131 has 2 divisors, whose sum is σ = 341032542132. Its totient is φ = 341032542130.
The previous prime is 341032542101. The next prime is 341032542139. The reversal of 341032542131 is 131245230143.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 341032542131 - 222 = 341028347827 is a prime.
It is a super-2 number, since 2×3410325421312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 341032542094 and 341032542103.
It is not a weakly prime, because it can be changed into another prime (341032542139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170516271065 + 170516271066.
It is an arithmetic number, because the mean of its divisors is an integer number (170516271066).
Almost surely, 2341032542131 is an apocalyptic number.
341032542131 is a deficient number, since it is larger than the sum of its proper divisors (1).
341032542131 is an equidigital number, since it uses as much as digits as its factorization.
341032542131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 341032542131 its reverse (131245230143), we get a palindrome (472277772274).
The spelling of 341032542131 in words is "three hundred forty-one billion, thirty-two million, five hundred forty-two thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •