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34104014325169 is a prime number
BaseRepresentation
bin1111100000100011101011…
…01010001100010110110001
311110202022102101200122112221
413300101311222030112301
513432230010131401134
6200311100133121041
710116635160516625
oct760216552142661
9143668371618487
1034104014325169
11a959481aa6728
1239a9705489181
131604cc1613249
1485c90094d185
153e21cc6235b4
hex1f0475a8c5b1

34104014325169 has 2 divisors, whose sum is σ = 34104014325170. Its totient is φ = 34104014325168.

The previous prime is 34104014325097. The next prime is 34104014325181. The reversal of 34104014325169 is 96152341040143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18566920834225 + 15537093490944 = 4308935^2 + 3941712^2 .

It is an emirp because it is prime and its reverse (96152341040143) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34104014325169 - 211 = 34104014323121 is a prime.

It is a super-2 number, since 2×341040143251692 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (34104014325569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17052007162584 + 17052007162585.

It is an arithmetic number, because the mean of its divisors is an integer number (17052007162585).

Almost surely, 234104014325169 is an apocalyptic number.

It is an amenable number.

34104014325169 is a deficient number, since it is larger than the sum of its proper divisors (1).

34104014325169 is an equidigital number, since it uses as much as digits as its factorization.

34104014325169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 34104014325169 in words is "thirty-four trillion, one hundred four billion, fourteen million, three hundred twenty-five thousand, one hundred sixty-nine".