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3410543312114 = 212781133422397
BaseRepresentation
bin110001101000010100001…
…110001111110011110010
3110002001012121221101200012
4301220110032033303302
5421334243041441424
611130440523254522
7501255304555301
oct61502416176362
913061177841605
103410543312114
1110a5448872564
12470ba007a442
131b97c7596a63
14bb0dd44a438
155dab1a6bb0e
hex31a1438fcf2

3410543312114 has 8 divisors (see below), whose sum is σ = 5116215273708. Its totient is φ = 1705138220880.

The previous prime is 3410543312081. The next prime is 3410543312129. The reversal of 3410543312114 is 4112133450143.

3410543312114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 3346576303225 + 63967008889 = 1829365^2 + 252917^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66685637 + ... + 66736760.

Almost surely, 23410543312114 is an apocalyptic number.

3410543312114 is a deficient number, since it is larger than the sum of its proper divisors (1705671961594).

3410543312114 is a wasteful number, since it uses less digits than its factorization.

3410543312114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 133435180.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 3410543312114 its reverse (4112133450143), we get a palindrome (7522676762257).

The spelling of 3410543312114 in words is "three trillion, four hundred ten billion, five hundred forty-three million, three hundred twelve thousand, one hundred fourteen".

Divisors: 1 2 12781 25562 133422397 266844794 1705271656057 3410543312114