Base | Representation |
---|---|
bin | 110001101001110001000… |
… | …000101010001111011011 |
3 | 110002012020010011221010221 |
4 | 301221301000222033123 |
5 | 421400440102001301 |
6 | 11131255213220511 |
7 | 501342006504526 |
oct | 61516100521733 |
9 | 13065203157127 |
10 | 3412100031451 |
11 | 10a6077572871 |
12 | 471355491737 |
13 | 1b99b4c57967 |
14 | bb20a0b5bbd |
15 | 5db5356bda1 |
hex | 31a7102a3db |
3412100031451 has 2 divisors, whose sum is σ = 3412100031452. Its totient is φ = 3412100031450.
The previous prime is 3412100031443. The next prime is 3412100031493. The reversal of 3412100031451 is 1541300012143.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3412100031451 - 23 = 3412100031443 is a prime.
It is not a weakly prime, because it can be changed into another prime (3412100031421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706050015725 + 1706050015726.
It is an arithmetic number, because the mean of its divisors is an integer number (1706050015726).
Almost surely, 23412100031451 is an apocalyptic number.
3412100031451 is a deficient number, since it is larger than the sum of its proper divisors (1).
3412100031451 is an equidigital number, since it uses as much as digits as its factorization.
3412100031451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 3412100031451 its reverse (1541300012143), we get a palindrome (4953400043594).
The spelling of 3412100031451 in words is "three trillion, four hundred twelve billion, one hundred million, thirty-one thousand, four hundred fifty-one".
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