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3412112012143 = 271128913617177
BaseRepresentation
bin110001101001110001101…
…110010111001101101111
3110002012020221201121120021
4301221301232113031233
5421401001133342033
611131300322103011
7501342213363622
oct61516156271557
913065227647507
103412112012143
1110a608330606a
124713594aaa67
131b99b7590c23
14bb20b913db9
155db54636b2d
hex31a71b9736f

3412112012143 has 16 divisors (see below), whose sum is σ = 3430355863680. Its totient is φ = 3393915033600.

The previous prime is 3412112012107. The next prime is 3412112012189. The reversal of 3412112012143 is 3412102112143.

3412112012143 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 3412112012143 - 229 = 3411575141231 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3412112012843) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 475419571 + ... + 475426747.

It is an arithmetic number, because the mean of its divisors is an integer number (214397241480).

Almost surely, 23412112012143 is an apocalyptic number.

3412112012143 is a deficient number, since it is larger than the sum of its proper divisors (18243851537).

3412112012143 is a wasteful number, since it uses less digits than its factorization.

3412112012143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10098.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 3412112012143 its reverse (3412102112143), we get a palindrome (6824214124286).

The spelling of 3412112012143 in words is "three trillion, four hundred twelve billion, one hundred twelve million, twelve thousand, one hundred forty-three".

Divisors: 1 271 1289 1361 7177 349319 368831 1754329 1944967 9251153 9767897 475423159 2507062463 2647100087 12590819233 3412112012143