3412131002233 has 4 divisors (see below), whose sum is σ = 3412135804048. Its totient is φ = 3412126200420.

The previous prime is 3412131002207. The next prime is 3412131002263. The reversal of 3412131002233 is 3322001312143.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3412131002233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3412131002198 and 3412131002207.

It is not an unprimeable number, because it can be changed into a prime (3412131002263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1100091 + ... + 2834512.

It is an arithmetic number, because the mean of its divisors is an integer number (853033951012).

Almost surely, 2^{3412131002233} is an apocalyptic number.

It is an amenable number.

3412131002233 is a deficient number, since it is larger than the sum of its proper divisors (4801815).

3412131002233 is an equidigital number, since it uses as much as digits as its factorization.

3412131002233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4801814.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 3412131002233 its reverse (3322001312143), we get a palindrome (6734132314376).

The spelling of 3412131002233 in words is "three trillion, four hundred twelve billion, one hundred thirty-one million, two thousand, two hundred thirty-three".