Base | Representation |
---|---|
bin | 110001101001110010110… |
… | …110110011100000110001 |
3 | 110002012022021110102022202 |
4 | 301221302312303200301 |
5 | 421401021014034132 |
6 | 11131302241112545 |
7 | 501342533656064 |
oct | 61516266634061 |
9 | 13065267412282 |
10 | 3412131002417 |
11 | 10a6092aa6805 |
12 | 471363928755 |
13 | 1b99bb4ac887 |
14 | bb2102588db |
15 | 5db56138762 |
hex | 31a72db3831 |
3412131002417 has 2 divisors, whose sum is σ = 3412131002418. Its totient is φ = 3412131002416.
The previous prime is 3412131002363. The next prime is 3412131002429. The reversal of 3412131002417 is 7142001312143.
3412131002417 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2917533870241 + 494597132176 = 1708079^2 + 703276^2 .
It is a cyclic number.
It is not a de Polignac number, because 3412131002417 - 216 = 3412130936881 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3412131002417.
It is not a weakly prime, because it can be changed into another prime (3412131002447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706065501208 + 1706065501209.
It is an arithmetic number, because the mean of its divisors is an integer number (1706065501209).
Almost surely, 23412131002417 is an apocalyptic number.
It is an amenable number.
3412131002417 is a deficient number, since it is larger than the sum of its proper divisors (1).
3412131002417 is an equidigital number, since it uses as much as digits as its factorization.
3412131002417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 29.
The spelling of 3412131002417 in words is "three trillion, four hundred twelve billion, one hundred thirty-one million, two thousand, four hundred seventeen".
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