Base | Representation |
---|---|
bin | 1111100001001011000010… |
… | …00110011101100000101011 |
3 | 11110211022221222101001211201 |
4 | 13300211201012131200223 |
5 | 13433101243412003121 |
6 | 200324512544505031 |
7 | 10121313613104334 |
oct | 760454106354053 |
9 | 143738858331751 |
10 | 34125144250411 |
11 | a96743531a265 |
12 | 39b182191b177 |
13 | 1606cab1187a6 |
14 | 85d946d2328b |
15 | 3e2a17686e91 |
hex | 1f096119d82b |
34125144250411 has 4 divisors (see below), whose sum is σ = 34130309255392. Its totient is φ = 34119979245432.
The previous prime is 34125144250339. The next prime is 34125144250427. The reversal of 34125144250411 is 11405244152143.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 34125144250411 - 243 = 25329051228203 is a prime.
It is a super-2 number, since 2×341251442504112 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34125144250441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2582492580 + ... + 2582505793.
It is an arithmetic number, because the mean of its divisors is an integer number (8532577313848).
Almost surely, 234125144250411 is an apocalyptic number.
34125144250411 is a deficient number, since it is larger than the sum of its proper divisors (5165004981).
34125144250411 is an equidigital number, since it uses as much as digits as its factorization.
34125144250411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5165004980.
The product of its (nonzero) digits is 76800, while the sum is 37.
The spelling of 34125144250411 in words is "thirty-four trillion, one hundred twenty-five billion, one hundred forty-four million, two hundred fifty thousand, four hundred eleven".
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