3412540400033 has 2 divisors, whose sum is σ = 3412540400034. Its totient is φ = 3412540400032.

The previous prime is 3412540400021. The next prime is 3412540400119. The reversal of 3412540400033 is 3300040452143.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2118445318144 + 1294095081889 = 1455488^2 + 1137583^2 .

It is a cyclic number.

It is not a de Polignac number, because 3412540400033 - 2¹² = 3412540395937 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3412540399969 and 3412540400005.

It is not a weakly prime, because it can be changed into another prime (3412540460033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706270200016 + 1706270200017.

It is an arithmetic number, because the mean of its divisors is an integer number (1706270200017).

Almost surely, 2^{3412540400033} is an apocalyptic number.

It is an amenable number.

3412540400033 is a deficient number, since it is larger than the sum of its proper divisors (1).

3412540400033 is an equidigital number, since it uses as much as digits as its factorization.

3412540400033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 29.

Adding to 3412540400033 its reverse (3300040452143), we get a palindrome (6712580852176).

The spelling of 3412540400033 in words is "three trillion, four hundred twelve billion, five hundred forty million, four hundred thousand, thirty-three".