Base | Representation |
---|---|
bin | 110001101010001011010… |
… | …001000001111101111010 |
3 | 110002020100211001121022112 |
4 | 301222023101001331322 |
5 | 421402340333434204 |
6 | 11131411030452322 |
7 | 501355635623501 |
oct | 61521321017572 |
9 | 13066324047275 |
10 | 3412540530554 |
11 | 10a628318a311 |
12 | 471458b040a2 |
13 | 1b9a552a900c |
14 | bb24c7bd838 |
15 | 5db7c08026e |
hex | 31a8b441f7a |
3412540530554 has 4 divisors (see below), whose sum is σ = 5118810795834. Its totient is φ = 1706270265276.
The previous prime is 3412540530527. The next prime is 3412540530559. The reversal of 3412540530554 is 4550350452143.
3412540530554 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 2060732025625 + 1351808504929 = 1435525^2 + 1162673^2 .
It is a super-4 number, since 4×34125405305544 (a number of 51 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (3412540530559) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 853135132637 + ... + 853135132640.
Almost surely, 23412540530554 is an apocalyptic number.
3412540530554 is a deficient number, since it is larger than the sum of its proper divisors (1706270265280).
3412540530554 is a wasteful number, since it uses less digits than its factorization.
3412540530554 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1706270265279.
The product of its (nonzero) digits is 720000, while the sum is 41.
Adding to 3412540530554 its reverse (4550350452143), we get a palindrome (7962890982697).
The spelling of 3412540530554 in words is "three trillion, four hundred twelve billion, five hundred forty million, five hundred thirty thousand, five hundred fifty-four".
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