Base | Representation |
---|---|
bin | 110001101010101110111… |
… | …111111100101111000011 |
3 | 110002021220121010110022111 |
4 | 301222232333330233003 |
5 | 421410102322014301 |
6 | 11131550324120151 |
7 | 501406535406442 |
oct | 61525677745703 |
9 | 13067817113274 |
10 | 3413140032451 |
11 | 10a6560627a26 |
12 | 4715a5836057 |
13 | 1b9b1c55bc76 |
14 | bb2a8276d59 |
15 | 5dbb4a00551 |
hex | 31aaeffcbc3 |
3413140032451 has 2 divisors, whose sum is σ = 3413140032452. Its totient is φ = 3413140032450.
The previous prime is 3413140032409. The next prime is 3413140032457. The reversal of 3413140032451 is 1542300413143.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3413140032451 - 215 = 3413139999683 is a prime.
It is a super-2 number, since 2×34131400324512 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3413140032457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706570016225 + 1706570016226.
It is an arithmetic number, because the mean of its divisors is an integer number (1706570016226).
Almost surely, 23413140032451 is an apocalyptic number.
3413140032451 is a deficient number, since it is larger than the sum of its proper divisors (1).
3413140032451 is an equidigital number, since it uses as much as digits as its factorization.
3413140032451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 3413140032451 its reverse (1542300413143), we get a palindrome (4955440445594).
The spelling of 3413140032451 in words is "three trillion, four hundred thirteen billion, one hundred forty million, thirty-two thousand, four hundred fifty-one".
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