Base | Representation |
---|---|
bin | 110001101010111011001… |
… | …011101011010000000001 |
3 | 110002022102211202002100212 |
4 | 301222323023223100001 |
5 | 421411012133330103 |
6 | 11132022505123505 |
7 | 501414566653034 |
oct | 61527313532001 |
9 | 13068384662325 |
10 | 3413344433153 |
11 | 10a6655a46226 |
12 | 471642189595 |
13 | 1b9b529c7325 |
14 | bb2c748301b |
15 | 5dbc79287d8 |
hex | 31abb2eb401 |
3413344433153 has 2 divisors, whose sum is σ = 3413344433154. Its totient is φ = 3413344433152.
The previous prime is 3413344433129. The next prime is 3413344433159. The reversal of 3413344433153 is 3513344433143.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2067820992064 + 1345523441089 = 1437992^2 + 1159967^2 .
It is a cyclic number.
It is not a de Polignac number, because 3413344433153 - 230 = 3412270691329 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3413344433153.
It is not a weakly prime, because it can be changed into another prime (3413344433159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706672216576 + 1706672216577.
It is an arithmetic number, because the mean of its divisors is an integer number (1706672216577).
Almost surely, 23413344433153 is an apocalyptic number.
It is an amenable number.
3413344433153 is a deficient number, since it is larger than the sum of its proper divisors (1).
3413344433153 is an equidigital number, since it uses as much as digits as its factorization.
3413344433153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 933120, while the sum is 41.
Adding to 3413344433153 its reverse (3513344433143), we get a palindrome (6926688866296).
The spelling of 3413344433153 in words is "three trillion, four hundred thirteen billion, three hundred forty-four million, four hundred thirty-three thousand, one hundred fifty-three".
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