Base | Representation |
---|---|
bin | 11111110010100011… |
… | …011110010101100011 |
3 | 10021002212102211010211 |
4 | 133302203132111203 |
5 | 1024401321003033 |
6 | 23403033234551 |
7 | 2315606354446 |
oct | 376243362543 |
9 | 107085384124 |
10 | 34134156643 |
11 | 13526929114 |
12 | 6747562a57 |
13 | 32aca29232 |
14 | 191b52165d |
15 | d4ba4e2cd |
hex | 7f28de563 |
34134156643 has 2 divisors, whose sum is σ = 34134156644. Its totient is φ = 34134156642.
The previous prime is 34134156631. The next prime is 34134156677. The reversal of 34134156643 is 34665143143.
It is a weak prime.
It is an emirp because it is prime and its reverse (34665143143) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34134156643 - 233 = 25544222051 is a prime.
It is a super-2 number, since 2×341341566432 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 34134156596 and 34134156605.
It is not a weakly prime, because it can be changed into another prime (34134156443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17067078321 + 17067078322.
It is an arithmetic number, because the mean of its divisors is an integer number (17067078322).
Almost surely, 234134156643 is an apocalyptic number.
34134156643 is a deficient number, since it is larger than the sum of its proper divisors (1).
34134156643 is an equidigital number, since it uses as much as digits as its factorization.
34134156643 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 311040, while the sum is 40.
Adding to 34134156643 its reverse (34665143143), we get a palindrome (68799299786).
The spelling of 34134156643 in words is "thirty-four billion, one hundred thirty-four million, one hundred fifty-six thousand, six hundred forty-three".
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