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3414044413001 is a prime number
BaseRepresentation
bin110001101011100100111…
…001111000110001001001
3110002101020121212202012102
4301223210321320301021
5421413430332204001
611132220152123145
7501441126461435
oct61534471706111
913071217782172
103414044413001
1110a6985081472
124717b86964b5
131b9c34a2a4a1
14bb3524139c5
155dc190e4e6b
hex31ae4e78c49

3414044413001 has 2 divisors, whose sum is σ = 3414044413002. Its totient is φ = 3414044413000.

The previous prime is 3414044412979. The next prime is 3414044413063. The reversal of 3414044413001 is 1003144404143.

3414044413001 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3413998985401 + 45427600 = 1847701^2 + 6740^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3414044413001 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (3414044413081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1707022206500 + 1707022206501.

It is an arithmetic number, because the mean of its divisors is an integer number (1707022206501).

Almost surely, 23414044413001 is an apocalyptic number.

It is an amenable number.

3414044413001 is a deficient number, since it is larger than the sum of its proper divisors (1).

3414044413001 is an equidigital number, since it uses as much as digits as its factorization.

3414044413001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 3414044413001 its reverse (1003144404143), we get a palindrome (4417188817144).

The spelling of 3414044413001 in words is "three trillion, four hundred fourteen billion, forty-four million, four hundred thirteen thousand, one".