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34143230131 is a prime number
BaseRepresentation
bin11111110011000110…
…000101100010110011
310021010111111210121221
4133303012011202303
51024411131331011
623403555525511
72316046444663
oct376306054263
9107114453557
1034143230131
1113530a6616a
12674a5b9897
1332b188516a
14191c8041a3
15d4c742971
hex7f31858b3

34143230131 has 2 divisors, whose sum is σ = 34143230132. Its totient is φ = 34143230130.

The previous prime is 34143230059. The next prime is 34143230137. The reversal of 34143230131 is 13103234143.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 34143230131 - 217 = 34143099059 is a prime.

It is a super-2 number, since 2×341432301312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34143230096 and 34143230105.

It is not a weakly prime, because it can be changed into another prime (34143230137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17071615065 + 17071615066.

It is an arithmetic number, because the mean of its divisors is an integer number (17071615066).

Almost surely, 234143230131 is an apocalyptic number.

34143230131 is a deficient number, since it is larger than the sum of its proper divisors (1).

34143230131 is an equidigital number, since it uses as much as digits as its factorization.

34143230131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 34143230131 its reverse (13103234143), we get a palindrome (47246464274).

The spelling of 34143230131 in words is "thirty-four billion, one hundred forty-three million, two hundred thirty thousand, one hundred thirty-one".