Base | Representation |
---|---|
bin | 11111110011000110… |
… | …000101100010110011 |
3 | 10021010111111210121221 |
4 | 133303012011202303 |
5 | 1024411131331011 |
6 | 23403555525511 |
7 | 2316046444663 |
oct | 376306054263 |
9 | 107114453557 |
10 | 34143230131 |
11 | 13530a6616a |
12 | 674a5b9897 |
13 | 32b188516a |
14 | 191c8041a3 |
15 | d4c742971 |
hex | 7f31858b3 |
34143230131 has 2 divisors, whose sum is σ = 34143230132. Its totient is φ = 34143230130.
The previous prime is 34143230059. The next prime is 34143230137. The reversal of 34143230131 is 13103234143.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34143230131 - 217 = 34143099059 is a prime.
It is a super-2 number, since 2×341432301312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 34143230096 and 34143230105.
It is not a weakly prime, because it can be changed into another prime (34143230137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17071615065 + 17071615066.
It is an arithmetic number, because the mean of its divisors is an integer number (17071615066).
Almost surely, 234143230131 is an apocalyptic number.
34143230131 is a deficient number, since it is larger than the sum of its proper divisors (1).
34143230131 is an equidigital number, since it uses as much as digits as its factorization.
34143230131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 34143230131 its reverse (13103234143), we get a palindrome (47246464274).
The spelling of 34143230131 in words is "thirty-four billion, one hundred forty-three million, two hundred thirty thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •