34151241433 has 4 divisors (see below), whose sum is σ = 34156250640. Its totient is φ = 34146232228.

The previous prime is 34151241391. The next prime is 34151241461. The reversal of 34151241433 is 33414215143.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-34151241433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34151241395 and 34151241404.

It is not an unprimeable number, because it can be changed into a prime (34152241433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2494363 + ... + 2508016.

It is an arithmetic number, because the mean of its divisors is an integer number (8539062660).

Almost surely, 2^34151241433 is an apocalyptic number.

It is an amenable number.

34151241433 is a deficient number, since it is larger than the sum of its proper divisors (5009207).

34151241433 is an equidigital number, since it uses as much as digits as its factorization.

34151241433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5009206.

The product of its digits is 17280, while the sum is 31.

Adding to 34151241433 its reverse (33414215143), we get a palindrome (67565456576).

The spelling of 34151241433 in words is "thirty-four billion, one hundred fifty-one million, two hundred forty-one thousand, four hundred thirty-three".