Base | Representation |
---|---|
bin | 110001101111101000110… |
… | …000100100110100001111 |
3 | 110002210111110022011022122 |
4 | 301233220300210310033 |
5 | 422001342414020033 |
6 | 11134220530203155 |
7 | 501654144662120 |
oct | 61575060446417 |
9 | 13083443264278 |
10 | 3418404048143 |
11 | 10a8811a70917 |
12 | 4726147234bb |
13 | 1ba47acc9856 |
14 | bb647422047 |
15 | 5ddc1c08a98 |
hex | 31be8c24d0f |
3418404048143 has 16 divisors (see below), whose sum is σ = 3916296384000. Its totient is φ = 2922902431200.
The previous prime is 3418404048109. The next prime is 3418404048167.
3418404048143 is nontrivially palindromic in base 10.
3418404048143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 3418404048143 - 212 = 3418404044047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3418404048094 and 3418404048103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3418404018143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11767358 + ... + 12054356.
It is an arithmetic number, because the mean of its divisors is an integer number (244768524000).
Almost surely, 23418404048143 is an apocalyptic number.
3418404048143 is a deficient number, since it is larger than the sum of its proper divisors (497892335857).
3418404048143 is a wasteful number, since it uses less digits than its factorization.
3418404048143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 291158.
The product of its (nonzero) digits is 589824, while the sum is 44.
The spelling of 3418404048143 in words is "three trillion, four hundred eighteen billion, four hundred four million, forty-eight thousand, one hundred forty-three".
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